Strangely works for 3/4 arrays

[gtrman97]

freeCodeCamp.org

So I wrote:

function largestOfFour(arr) {

for (var i=0; i<arr.length; i++) {
    var biggest = arr[i][0]; 
  for (var j=0; j<arr[i].length; j++) {
    if(arr[i][j] > biggest) {
      biggest = arr[i][j]; 
      console.log(biggest);  
    }
  }
}

  return arr;
}

For the input largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);

It prints out 5, 27, 35, 37, 39, 1001 so it worked for the first two sub-arrays and the last one, but not the third one.

[JeremyLT]

@gtrman97

return arr;

Why are you returning arr?

[ilenia]

@gtrman97

35, 37, 39

these comes from the third array

@gtrman97

[32, 35, 37, 39]

with this it starts

@gtrman97

var biggest = arr[i][0];

the value of biggest starts at 32

@gtrman97

    if(arr[i][j] > biggest) {
      biggest = arr[i][j]; 
      console.log(biggest);  
    }

then there is 35, this is now the value of biggest, and it is printed
then there is 37, this is now the value of biggest because it is bigger than 35 and it is printed
same for 39
it does exactly what you have written it to do

you are not doing anything with the biggest values of the arrays as you are required to do instead