Stuck at Learn Bash and SQL by Building a Bike Rental Shop

Backend Development
1

Hello everyone, i stuck at this topics
"When a user enters an option at the main menu, you want to take them to the appropriate sub-menu. You can use a case statement for this. Here’s an example:

case EXPRESSION in
  PATTERN) STATEMENTS ;;
  PATTERN) STATEMENTS ;;
  PATTERN) STATEMENTS ;;
  *) STATEMENTS ;;
esac

The expression you want is the $MAIN_MENU_SELECTION variable. You are expecting it to be a 1, 2, or 3 for your various menus. Add a case statement that takes users to their corresponding menus. The * is for when anything else is entered. Take users to the MAIN_MENU when the variable isn’t a 1, 2, or 3."

I’ve been following the hint. This is my code =


#!/bin/bash

echo -e "\n~~~~~ Bike Rental Shop ~~~~~\n"

MAIN_MENU() {
  echo "How may I help you?" 
  echo -e "\n1. Rent a bike\n2. Return a bike\n3. Exit "
  read MAIN_MENU_SELECTION
  
  case $MAIN_MENU_SELECTION in
  1) RENT_MENU ;;
  2) RETURN_MENU ;;
  3) EXIT ;;
  *) MAIN_MENU ;;
esac

}

RENT_MENU() {

}

RETURN_MENU() {
echo "Return Menu"
}

EXIT() {
  echo -e "\nThank you for stopping in.\n"
}

MAIN_MENU

The error notice is “Your script should take you to the various menus and ouput the correct text”

Could you please help me understand why this is happening? I appreciate your attention and help. Thank you.

2

I don’t know if it will help but I would indent the esac to match the case and indent the inner block a bit more. Basically make it look like the example.