Tell us what’s happening:777
Your code so far
const sum = (function() {
"use strict";
return function sum(... z) {
return z.reduce((a,b,...z) => a + b, 0);
};
})();
console.log(sum(1, 2, 3)); // 6
how can i do this " The sum
function uses the ...
spread operator on the args
parameter."
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.
Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-the-rest-operator-with-function-parameters