Ternary Operator confuse

[cihatsaman]

return elem
    ? !Array.isArray(elem)
      ? steamrollArray(arr, [elem, ...flatArr])
      : steamrollArray(arr.concat(elem), flatArr)
    : flatArr;

I want to use regular if-else cases instead of using ternary operators so how can I revert that block code from ternary operator to regular if-else this block code?

My code as below :

  if (steamrollArray(arr, [elem, ...flatArr])) {
      return elem;
    } else {
      steamrollArray(arr.concat(elem), flatArr);
    }
  } else {
    flatArr;
  }

[JeremyLT]

You will need a return statement in each of your cases.

Also, I’m not sure that you pulled apart the ternary correctly.

@cihatsaman

return elem /* condition1 */
    ? !Array.isArray(elem) /* result if condition1 is true, which is another if */
      ? steamrollArray(arr, [elem, ...flatArr]) /* result if condition2 is true and condition1 is true */
      : steamrollArray(arr.concat(elem), flatArr) /* result if condition2 is false but condition1 is true */
    : flatArr; /* result if condition1 is false */

[cihatsaman]

is it possible to put your code on the solution, please?

[JeremyLT]

Nope, for two reasons

1. I don’t have enough of the original code to work with here
2. I’d rather help you modify your code than do it for you

[jsdisco]

To get you started, I’ll simplify it a bit:

return elem
    ? firstOption
    : secondOption;

With if-else, this would be

if (elem) {
  return firstOption
} else {
  return secondOption
}

[cihatsaman]

Thank you for clear explaining I understood what I am missing…