Type error 1 is not a function

JavaScript
1 

function diffArray(arr1, arr2) {
  var newArr = [];
  
  for(var i=0;i<arr1.length;i++){
    if(arr2.find(arr1[i]) == -1){
      newArr.push(arr1[i]);
    }
  }
for(var i=0;i<arr2.length;i++){
    if(arr1.find(arr2[i]) == -1){
      newArr.push(arr2[i]);
    }
  }
  return newArr;
}

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]);
2

Can you provide a link to the challenge?

3
4

I cannot find what is wrong, but I know it is because of this input

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]);

but it shouldn’t do that. Maybe you can try a different approach on how you compare them?

5

these are simple arrays , error is in if condition

6

find() requires function argument ,I’m using indexOf() now,passed lesson