Understanding Undefined Value returned from a Function passing with any sum?

JavaScript
1

Tell us what’s happening:

Im confused on why this is passing me. How does the sum = 8?

Also, it allowed me to pass with this. How so?


var sum = 12;
function addFive() {
  sum = sum + 5;
}

Your code so far


// Example
var sum = 0;
function addThree() {
  sum = sum + 3;
}

// Only change code below this line
var sum = 0;
function addFive() {
  sum = sum + 5;
}


// Only change code above this line
var returnedValue = addFive();

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.131 Safari/537.36.

2

what’s the challenge? without that is not possible to say why it is passing or not

anyway, your function return undefuned because it is not returning something else (there is not a return statement that returns something different)

1 Like
3

the code running behind the scenes is why it is passing you. all they are looking for is your solution to match:

function addFive() { 
    sum = sum + 5;
}

you are not supposed to declare the sum variable again, but it doesn’t matter if you do because the code running behind the scenes resets the ‘sum’ variable to 0 before running the ‘addThree()’ and ‘addFive()’ functions.

1 Like
4

Ahh okay thanks, guess I was just overthinking it.

5

https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/understanding-undefined-value-returned-from-a-function