Use Caution When Reinitializing Variables Inside a Loop: 2D array

Tell us what’s happening:

``````
function zeroArray(m, n) {
// Creates a 2-D array with m rows and n columns of zeroes
let newArray = [];
let row = [];
for (let i = 0; i < m; i++) {
// Adds the m-th row into newArray

for (let j = 0; j < n; j++) {
// Pushes n zeroes into the current row to create the columns
row[i,j]=[0,0]
}
// Pushes the current row, which now has n zeroes in it, to the array
newArray.push(row);
}
return newArray;
}

let matrix = zeroArray(3, 2);
console.log(matrix);

``````

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Challenge: Use Caution When Reinitializing Variables Inside a Loop

``````function zeroArray(m, n) {
// Creates a 2-D array with m rows and n columns of zeroes
let newArray = [];
let row = [];
for (let i = 0; i < m; i++) {
// Adds the m-th row into newArray
row = [];
for (let j = 0; j < n; j++) {
// Pushes n zeroes into the current row to create the columns
row.push(0);
}
// Pushes the current row, which now has n zeroes in it, to the array
newArray.push(row);
}
return newArray;
}

let matrix = zeroArray(3, 2);
console.log(matrix);
``````

With this way you can pass the tests. You should add ` row = [];` when i increases by 1.

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you have two many elvels in your array

``````[ [ [ 0, 0 ], [ 0, 0 ] ],
``````[[0, 0], [0, 0], [0, 0]]