Use Recursion to Create a Countdown_6.21.21

[manbodhclaude]

Hello, In this exercise I have to write a function called countDown where it takes in an argument of type integer (n) and will print out n - 1 in descending order, so if 4 was passed in as (n) when I run code I should get 4, 3, 2, 1. So far in my code I have been able to simply print out these numbers however Im having an issue understanding how to push these numbers into a new array which is apart of what the original question wants me to do.

function countDown(n) {
  if (n < 1) {
    return [];
  } else {
    console.log(n);
    const countDecrease = countDown(n - 1);
    countDecrease.push(n);
    return countDecrease;
  }
}

countDown(4);
       

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Challenge: Use Recursion to Create a Countdown

Link to the challenge:

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[Sylvant]

if you use console.log(countDown(4)) you will notice your function returns [1,2,3,4], so you are pretty close. You must find a way to push the numbers in reverse, or maybe push the array which is retarned from calling your function to the previous n? if that makes sense

Lets say for example countDown(4) should return [4,3,2,1]. What countDown(5) should return? [5,4,3,2,1] So countDown(5) would be returning [5, ...countDown(4)] right? Just need to find a way how to write that in the function logic.