Tell us what’s happening:
Why can’t I use spread operator in const args ? “n” is also an array of arguments right?
Your code so far
const sum = (function() {
"use strict";
return function sum(...n) {
const args = [...n];
return args.reduce((a, b) => a + b, 0);
};
})();
console.log(sum(1, 2, 3)); // 6
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.
Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-the-rest-operator-with-function-parameters