Whats wrong with this code i think it should work 😐

JavaScript
1 

function getIndexToIns(arr, num) {
let newArray = arr.sort(function (a, b) {
  return a - b;
});
let ans = "";
for (let i = 0; i < newArray.length; i++) {
  if (newArray[i] >= num) {
     return ans = i;
  } else {
     ans = newArray.length;
  }
}
if(newArray === []){
  return ans = 0;
}
return ans;
};

console.log(getIndexToIns([], 35));

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2

Hi @meetb !

I get what you are trying to do here

But that is not the way to go about it.

You basically want to say if there are no items in the array then return 0.

Here is the psuedo code

if(arr.length equals zero){
return zero
}

Just check if the non sorted array has zero elements and return zero.
It will work with the sorted array too but there is no point in sorting an empty array.

IMO that should be the first condition in your code before you sort the array.

Hope that helps!

3

Thank you so much once again @jwilkins.oboe. You have always helped me out in all troubles in the most accurate way. [Hope you remember me as I raised many topics and you have solved them :sweat_smile: :sweat_smile:]

1 Like
4

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