Wherefore art thou

Ahhhhh okay, so object.values isn’t needed for this. Noted

function whatIsInAName(collection, source) {

let keysInSource = Object.keys(source);

  return collection.filter(item => {
    for (let i = 0; i < keysInSource.length; i++) {
      if (item[keysInSource[i]] !== source[keysInSource[i]]) {
        return false;
    return true;

console.log(whatIsInAName([{ first: "Romeo", last: "Montague" }, { first: "Mercutio", last: null }, { first: "Tybalt", last: "Capulet" }], { last: "Capulet" }));

Finally got it. Kind of feels like I cheated by looking at so many different things on the internet. Can’t wait until I get to a point where I’m getting through problems without so much help. But just to go over this solution one last time. I want to make sure I fully understand each line of code. It took me a long time because I honestly couldn’t think of putting a for loop within the filter, I don’t recall ever having to do that.

So this code is basically giving the keys of source a name. Then filtering the collection arrays so that if a item in the collection is not equal to the source…then it will return false, but if it is equal it will return that array as the answer