“Specify Upper and Lower Number of Matches”
let ohStr = "Ohhh no";
let ohRegex = /.h{3,6}[^h]+/; // Change this line
let result = ohRegex.test(ohStr);
The result is
// running tests
Your regex should not match the string Ohhhhhhh no
// tests completed
Challenge: Specify Upper and Lower Number of Matches
Link to the challenge:
The .
in regex matches any character. Would h be any character?
The .
in my solution would match any first character, which is “O”
What I’m having trouble with is why doesn’t my [^h]+
work? I understand it as “match anything that is not “h” until the end of the string”
as your regex does not have any indication on start or end of string, the .
matches an “h”, and the h{3,6}
matches the other 6, so the [^h]+
, after the "h"s, no other “h”, but before? .
matches any character, “h” included
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I’m sorry but why .
would match an “h” and not the “O”?
And i didn’t quite understand this part.
Thank you
Because its just shifting over and the .
will find the first h, and h{3,6}
will then find 3-6 more h’s, so possibly 7 h’s. Then [^h]+
then finds the no
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