**Tell us what’s happening:**

I have one question, In the parameters, I was using for example (…z), why this parameter can’t be returned.

obligatory the example has to use (…args)?

**Your code so far**

```
const sum = (function() {
"use strict";
return function sum(...args) {
return args.reduce((a,b) => a + b, 0);
};
})
();
console.log(sum(1,2,3));//6,
```

**Your browser information:**

User Agent is: `Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36`

.

**Link to the challenge:**

https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-the-rest-operator-with-function-parameters/