Why is this not a valid number (telephoneCheck("55 55-55-555-5"));

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.

   **Your code so far**


function telephoneCheck(str) {
 if (str.indexOf("(") === -1 && str.indexOf(")") > -1){
   return false
 }

 if (str.indexOf(")") - str.indexOf("(") >= 5){
   return false;
 }
 if (str[0] === "-") return false;
let polishedString = str.replace(/\-| /g , "");
console.log(polishedString)

if (polishedString.indexOf("(") < polishedString.indexOf(")")) {
 polishedString = polishedString.replace(/\(|\)/g, "")
 console.log(polishedString)
 
}
console.log(polishedString)

 if (polishedString.length === 10) {
 return true;
}else if (polishedString.length === 11 && polishedString[0] === "1") {
 return true;
}

 return false;
}

console.log(telephoneCheck("55 55-55-555-5"));

   **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.212 Safari/537.36 OPR/76.0.4017.227

Challenge: Telephone Number Validator

Link to the challenge:

2

it does not have the 3-3-4 pattern of a valid number format

3

Tell us what’s happening:
Describe your issue in detail here.

   **Your code so far**


function telephoneCheck(str) {
 if (str.indexOf("(") === -1 && str.indexOf(")") > -1){
   return false
 }

 if (str.indexOf(")") - str.indexOf("(") >= 5){
   return false;
 }
 if (str[0] === "-") return false;
let polishedString = str.replace(/\-| /g , "");
//console.log(polishedString.length)

if (polishedString.indexOf("(") < polishedString.indexOf(")")) {
 polishedString = polishedString.replace(/\(|\)/g, "")
 console.log(polishedString)
 
}
console.log(polishedString.length)

if (polishedString.length === 10) {
 return true;
}else if (polishedString.length === 11 && polishedString[0] === "1") {
 return true;
}

 return false;
}

console.log(telephoneCheck("55 55-55-555-5"));

   **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.212 Safari/537.36 OPR/76.0.4017.227

Challenge: Telephone Number Validator

Link to the challenge:

4

So how can I add that condition in code.

5

I think you need to think a bit more on how to verify a number
the lines I quoted is where you evaluate the dashes and then eliminate them, but you are checking only for the presence at the beginning

6

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