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Question: Basic JavaScript: Use Recursion to Create a Range of Numbers.
We have defined a function named rangeOfNumbers
with two parameters. The function should return an array of integers which begins with a number represented by the startNum
parameter and ends with a number represented by the endNum
parameter. The starting number will always be less than or equal to the ending number. Your function must use recursion by calling itself and not use loops of any kind. It should also work for cases where both startNum
and endNum
are the same.
the answer is :
function rangeOfNumbers(startNum, endNum) {
if (endNum - startNum === 0) {
return [startNum];
} else {
var numbers = rangeOfNumbers(startNum, endNum - 1);
numbers.push(endNum);
return numbers;
}
}
Your code so far
function rangeOfNumbers(startNum, endNum) {
if(endNum - startNum === 0) {
return [startNum];
}
else {
var numbers = rangeOfNumbers(startNum++, endNum);
numbers.push(startNum);
return numbers;
}
};
console.log(rangeOfNumbers(3,6));
don’t understand why using startNumber++ causes endless loop.
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Challenge: Use Recursion to Create a Range of Numbers
Link to the challenge: