Tell us what’s happening: Describe your issue in detail here. Your code so far function multiplyAll(arr) { let product = 1; // Only change code below this line // Only change code above this line return product; } multiplyAll([[1, 2], [3, 4], [5, 6, 7]]); Your browser information: Use…

that will be six ,if I need to do arithmetic

Yes. 1*2*3 is equal to 6 [image] JeremyLT: multiplyAll([[1], [2], [3]]) should return 6 Which is what this test is saying here. If you multiply all of the numbers in all of the subarrays together, you get 6. multiplyAll([[1, 2], [3, 4], [5, 6, 7]]) should return 5040 This one is saying …

[image] JeremyLT: multiplyAll([[1, 2], [3, 4], [5, 6, 7]]) должен вернуться 5040 multiplyAll([[1, 2], [3, 4], [5, 6, 7]]) должен вернуться 5040 I understand the arithmetic, but I don’t understand how this happens in the code, where everything is added, why first it came out 2, then 24 and af…

Well, there isn’t code for this yet. You need to write it! The example showed how to loop over an array. Do you have questions about the example?

Using the example, I understand how it works, but what I asked you is not clear to me.

Can you write a loop that console.logs each subarray of the arr?

Ok, here you’re actually printing out each element of the subarrays, but this is what I was going to ask for next. You have each number in each subarray. Can you multiply product by each arr[i][j]?

Basic JavaScript - Nesting For Loops

Programming JavaScript

JeremyLT December 4, 2023, 4:29pm 36

Give it a try

Basic JavaScript - Replace Loops using Recursion

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