Build a Time Calculator Project - Build a Time Calculator Project

Python
22

I do not see that issue with your code, but the last code you posted was 9 days ago, did you make any changes since then? can you post your updated code?

23

No, here is my code as it stands right now:

def add_time(start, duration, day_of_week=''):
    start_m = start[-2:]  # Extract AM/PM
    start_hour = int(start.split(':')[0])

    if start_hour == 12 and start_m == 'AM':
        start_hour = 0
    if start_hour == 12 and start_m == 'PM':
        start_hour = 12
    if start_m == 'PM':
        start_hour += 12
    
    start_min = int(start[-5:-3])
    duration_hour = int(duration.split(':')[0])
    duration_min = int(duration.split(':')[1])

    week = ['monday','tuesday','wednesday','thursday','friday','saturday','sunday']
    extra_day = 0
    new_day = ''
    new_m = ''

    new_min = start_min + duration_min
    if new_min >= 60:
        duration_hour = duration_hour + new_min // 60
        new_min %= 60
    if new_min == 0:
        new_min = '00'
    if new_min > 0 and new_min < 10:
        new_min = f'0{new_min}'

    new_hour = start_hour + duration_hour
    if new_hour >= 24:
        extra_day = new_hour // 24
        new_hour %= 24
    if new_hour < 12:
        new_m = 'AM'
    if new_hour >= 12 and new_hour < 24:
        new_m = 'PM'
        new_hour -= 12
    if new_hour == 0:
        new_hour = 12

    if day_of_week != '':
        day_of_week = day_of_week.lower()
        day_index = week.index(day_of_week)
        new_day_of_week = week[(day_index + extra_day) % 7].capitalize()
    
    if extra_day == 1:
        new_day = '(next day)'
    if extra_day > 1:
        new_day = f'({extra_day} days later)'
    
    if day_of_week == '':
        new_time = f'{new_hour}:{new_min} {new_m}{new_day}'
    else:
        new_time = f'{new_hour}:{new_min} {new_m}, {new_day_of_week} {new_day}'

    
    return new_time

print(repr(add_time('3:30 PM', '2:12')))
print(repr(add_time('8:16 PM', '466:02', 'tuesday') ))
24

Hi @jcant

See if you can fix this case:

image

Happy coding

25

that is what i am confused about… because my return statement for this is:

if day_of_week == '':
        new_time = f'{new_hour}:{new_min} {new_m}{new_day}'

and next day is stored in new day.
this is what i don’t understand

26

What happens when you add a single space between these two variables?:

27

it messes up the other tests

28

You know what the problem is, you just need to fix it.

Code the output so that when “next day” is needed, it has a space in front of it, and when it’s not, you don’t add a trailing space.

{new_m} {new_day}'

If {new_day} is empty then your string will end with a space, which is not wanted.

29

when I do this it fails the other tests, so that doesn’t work

30

Hi @jcant

You will need to fix up the other tests that were previously passing.

31

When you do what? You’ll need to try something different then.

32

yes, that is why i am here asking for help. i don’t know what to do and am learning this. i have tried finding the answers on my own with no luck

33

At the moment your code is producing this result:

image

When using the following code:

Is there another way you could approach the problem?

34

figured out my issue. thanks

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