I had answer very similar to basic code, using a ternary operator, in hindsight I could’ve condensed it down to the basic solution
function confirmEnding(str, target) {
return (str.substr(-target.length) == target) ? true : false;
}
confirmEnding("Bastian", "n");
my code:
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
for (var x=0 ;x < str.length; x++) {
if (str.substring(str.length-x) === target.substring(target.length-4,target.length))
return true;
}
return false;
}
confirmEnding(“Bastian”, “n”);
Hello, i used slice for solve the challenge.
Here is my code
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
return str.slice(-target.length) == target;
}
confirmEnding(“Bastian”, “n”);
As always here is my new way to do it
function confirmEnding(str, target) {
// "Never give up and good luck will find you."
// -- Falcor
return str.substr(-target.length) === target;
}
My solution was pretty much the same as the basic code answer. However I did try to solve it with the .endWith() method as well. I’ll include that below for comparison.
function confirmEnding(startOfString, endOFString) {
return startOfString.substr(-endOfString.length) === endOfString;
}
confirmEnding("Bastian", "n");
Personally I like this solution better as it seems much simpler to understand and requires a little bit less code
function ending(startOfString, endOfString) {
return startOfString.endsWith(endOfString);
};
ending("Pickle", "t");Alright, here’s my code for this exercise:
function confirmEnding(str, target) {
var array= str.split(" ");
if (str.substr(str.length-target.length) == target){
return true;
} else if (array.length>1 && array[array.length-1] == target ){
return true;
}
return false;
}
confirmEnding(“Bastian”, “n”);
I got a similar code but used .substring instead of .substr
function confirmEnding(str, target) {
if (str.substring(str.length - target.length) === target) {
return true;
}
return false;
}
My solution:
function confirmEnding(str, target) {
if(str.substring(str.length - target.length) === target) {
return true;
} else {
return false;
}
}
confirmEnding(“Bastian”, “n”);
Hi everyone, I solved this using the string method .includes() after I split the sentence/word into an array of words/letters. Do you think this is cheating or is this fine?
function confirmEnding(str, target) {
var splitStr;
if (str.includes(" "))
splitStr = str.split(" ");
else
splitStr = str.split("");
var lastPart = splitStr[splitStr.length - 1];
return lastPart.includes(target);
}
confirmEnding("Bastian", "n");Hey campers,this was my approach:
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
var lastIndexOf = target;
if(str.lastIndexOf(target) == (str.length - target.length));
return str.lastIndexOf(target) == (str.length - target.length);
}
confirmEnding(“Bastian”, “n”);
Hi all,This is how I did it.
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
var ne = str.substring(str.length -target.length);
if (ne === target){
return true;
}
return false;
}
confirmEnding(“Bastian”, “n”);
// This is what I got :
function confirmEnding(str, target) {
return str.substr(str.length-target.length,target.length) === target;
}
Hi guys this is my take on the problem:
function confirmEnding(str, target) {
// “Never give up and good luck will find you.”
// – Falcor
var car = str.split(’’);
var cCar = target.split(’’);
if(target == str.substr( car.length - cCar.length))
return true;
else
return false;
}
confirmEnding(“He has to give me a new name”, “name”);
Would like to know what’s there to improve on this…
I think this is Basic Code Solution
Checking if here is one word or more and our solution goes to the right branch
function confirmEnding(str, target) {
var arr = str.split(' ');
if (arr.length > 1) {
return arr[arr.length - 1].substring(arr[arr.length -1].length - 1 - (target.length - 1)) == target ;
} else {
return str[str.length - 1] == target ;
}
}A little similar
function confirmEnding(str, target) {
return str.split(' ').pop().substr(str.split(' ').pop().length-(target.length),target.length)===target;
}
confirmEnding(“Bastian”, “n”);
This is how I was able to solve the problem. Hey it worked 
edit* Made it easier to read the code
function confirmEnding(str, target) {
// "Never give up and good luck will find you."
// -- Falcor
str = str.split(' ');
for (x = 0; x < str.length; x++) {
lastWord = str[x];
}
lastWord = lastWord.split('').reverse();
target = target.split('').reverse();
var j = true;
for (i = 0; i < target.length; i++) {
if (target[i] !== lastWord[i]) {
j = false;
} else j = true;
} return j;
}function confirmEnding(str, target) {
return str.substring(str.length - target.length) === target;
}
confirmEnding("Bastian", "n");function confirmEnding(str, target) {
return (target == str.substr(str.length - target.length, target.length));
}
confirmEnding("Bastian", "n");function confirmEnding(str, target) {
var splited = str.split(" ");
if (target === splited[splited.length-1]) {
return true;
}
else if (target === str[str.length-1]) {
return true;
}
else if (target === splited[splited.length-1].substring((splited[splited.length-1].length - target.length))){
return true;
}
else {
return false;
}
}
After hour… Guess i am bad too . Nevermind
my solution
function confirmEnding(str, target) {
var amount = target.length;
var finalChar = str.substr(-amount, amount);
if (finalChar === target){
return true;
}
return false;
}After seeing the other answers, I am a little embarrassed. But this is what I got:
function confirmEnding(str, target) {
if (str.substr(-1) == target) {
return true;
} else if (str.substr(-target.length) == target) {
return true;
} else {
return false;
}
}
confirmEnding("Bastian", "n");