Slice() method question

[alhazen1]

@bananahair

for(let i = 0; i < arr.length; i++){ var oneArr = arr.slice(i);} return arr; } chunkyArrayInGroups([“a”, “b”, “c”, “d”], 2);

When I console.log (oneArr) this is what I receive:

[ 'a', 'b', 'c', 'd' ] [ 'b', 'c', 'd' ] [ 'c', 'd' ] [ 'd' ]

Why is it depreciating like that?
My guess is that it is just looping through and slicing off an element each time it iterates through the sequence.

Because that’s what slice does…

from MDN: The slice() method returns a shallow copy of a portion of an array into a new array object selected from begin to end ( end not included ). The original array will not be modified.

As you loop from 0 to 3
arr.slice(0) is [ ‘a’, ‘b’, ‘c’, ‘d’ ] (index 0 to end of array)
arr.slice(1) is [ ‘b’, ‘c’, ‘d’ ]
arr.slice(2) is [ ‘c’, ‘d’ ]
arr.slice(3) is [ ‘d’ ] (index 3 to end of array)

This is all covered in detail on MDN page for array .slice() method

Array.prototype.slice() - JavaScript | MDN

@bananahair

That said, when I do this:
var oneArr = arr[i].slice(i);

My console log returns a

Why? I’m perplexed by this? Is it because it stops at the first iteration?

String has a similar slice() method.
when i is 0 arr[i] is ‘a’, a string of one character and ‘a’.slice(0) is ‘a’ (index 0 to end of string)
when i is 1 arr[i] is ‘b’ and ‘b’.slice(1) is an empty string (index 1 to end of string)

Also covered in detail by the MDN

String.prototype.slice() - JavaScript | MDN

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