Learn Functional Programming by Building a Spreadsheet - Step 85

JavaScript
1

Tell us what’s happening:

i don’t know how to solve this challenge
Your apply function should call the spreadsheetFunctions[fn.toLowerCase()] function.

Your code so far

// User Editable Region

const applyFunction = str => {
  const noHigh = highPrecedence(str);
  const infix = /([\d.]+)([+-])([\d.]+)/;
  const str2 = infixEval(noHigh, infix);
  const functionCall = /([a-z0-9]*)\(([0-9., ]*)\)(?!.*\()/i;
  const toNumberList = args => args.split(",").map(parseFloat);
  const apply = (fn, args) => spreadsheetFunctions[fn.toLowerCase()].toNumberList(args);
}

// User Editable Region

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Challenge Information:

Learn Functional Programming by Building a Spreadsheet - Step 85

2

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').

3

A question for you. Do you understand what the value of spreadsheetFunctions[fn.toLowerCase()] is?

1 Like
4

Hi @mahdaouiilyas

Pass in the result of calling toNumberList with args as an argument.

You code has it as a method rather than a call.

Happy coding

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5

fn represent the key inside spreadsheetFunctions object, and it will access a function based on the fn value . right!!!

6

If you are saying that spreadsheetFunctions[fn.toLowerCase()] resolves to the name of a function then you are correct. And then of course you call a function using parentheses, passing in any arguments to the function inside of the parentheses.

1 Like