Learn String Manipulation by Building a Cipher - Step 42

Python
1

Tell us what’s happening:

What am I doing wrong here exactly?
I tried a plethora of different things but the code either didn’t run at all or it didn’t pass.
I’d appreciate any help,

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
     if char == ' ':
      print('space!)
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

2

You have indentation issues. Notice that index should be align with if.

3 
for char in text.lower():
    if char == ' ':
    print(space!)
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

I tried this, still didn’t work

4

Remove one blank space in front of the if.

5

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').

1 Like
6

You need to indent each code block. It’s the only way Python can tell which code is part of the for or if blocks.

code
code

for this in that:
    code
    code
    if this == that:
        code
        code
    code
    code

code
code
1 Like
7

an other issue is that you need to put quotes around space!