A question about 'return'

JavaScript
1

Hello guys!

I was wandering why the last return is after the for loop and not after if statement? I couldn’t pass the test becouse i thought that return ‘No such contact’ should be after i close ** if (name===contacts[i].firstName )** statement , like if… else…

Can you explain me please?

Your code so far


// Setup
var contacts = [
{
    "firstName": "Akira",
    "lastName": "Laine",
    "number": "0543236543",
    "likes": ["Pizza", "Coding", "Brownie Points"]
},
{
    "firstName": "Harry",
    "lastName": "Potter",
    "number": "0994372684",
    "likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
    "firstName": "Sherlock",
    "lastName": "Holmes",
    "number": "0487345643",
    "likes": ["Intriguing Cases", "Violin"]
},
{
    "firstName": "Kristian",
    "lastName": "Vos",
    "number": "unknown",
    "likes": ["JavaScript", "Gaming", "Foxes"]
}
];


function lookUpProfile(name, prop){
// Only change code below this line
for (let i = 0; i < contacts.length; i++) {

    if (name===contacts[i].firstName ) {
    
        if (contacts[i].hasOwnProperty(prop)) {
            return contacts[i][prop];
            } else {
                return 'No such property';
                }
    }  

}
return 'No such contact'
// Only change code above this line
}

lookUpProfile("Akira", "likes");

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.61 Safari/537.36.

Challenge: Profile Lookup

Link to the challenge:

2

You can’t say that there are no contacts that match if you haven’t fully gone through the entire for loop to check all contacts.

3

when a return statement is met, the functions stops and return a value

if you put the return statement there, the loop will never change the value of i, and the only element in the array that is checked is the first

1 Like
4

I see now. Thank you!