Hello everyone, well i would like to log the sum of numbers in the hash1 that are not present in the hash2 ! am getting 0 any help ? thank you in advance.
let hash1 = {
'2': 0,
'3': 1,
'4': 2,
'8': 3,
'5': 4,
};
let hash2 = {
'2': 0,
'7': 1,
'9': 2,
'5': 3,
'1': 4,
}
let totHash = 0;
for(i = 0; hash1.length = 0; i++){
if(hash1[i] === hash2[i]){
totHash = totHash + hash1[i]
}
}
console.log(totHash)
Sky020
September 7, 2020, 2:55pm
2
Hello there,
Have a re-read of this line:
for(i = 0; hash1.length = 0; i++){
Also, how do you expect to go through each number, if each hash is an object literal?
Hope this helps
1 Like
Ah thank you just change it, even it’s first time working with objects exercise, thought it’s the same as arrays, and now am getting stuck
ilenia
September 7, 2020, 5:25pm
4
you neef a for…in loop for an object
also, check the hasOwnProperty
method
1 Like
Thank you, for your time and answers !!
i found the solution !!
let hash1 = {
'8': 0,
'3': 1,
'4': 2,
'2': 3,
'5': 4,
};
let set2 = [8, 7, 9, 5, 3]
let totHash = 0;
for(let i = 0; i < set2.length ; i++){
if(hash1[set2[i].toString()] !== undefined){
console.log(set2[i])
totHash += set2[i]
};
}
totHash = totHash*2;
console.log(totHash)