Basic Algorithm Scripting - Mutations

JavaScript
1

Just not sure whats wrong here
Your code so far

function mutation(arr) {
  let source = arr[0].toLowerCase();
  let mutant = arr[1].toLowerCase();
  let sourceArr = arr[0].split(" ")
  let mutantArr = arr[1].split(" ")
  let count = 0;

  for(let i = 0; i < mutant.length; i += 1 ){
    let check = mutant[i];

    
    if(source.includes(check)){
      count= count + 1
    }
  }

  if(count === mutant.length){
    return true

  }
  
  return false;
}

mutation(["hello", "hey"]);

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Challenge: Basic Algorithm Scripting - Mutations

Link to the challenge:

2

I’m not immediately sure either. Have you tried console logging intermediate results?

3

it works for all things false

4

Have you tried logging out intermediate variables? Do the arrays hold what you expect?

5

yea each variable is as desired… i havent confirmed the functionality of the syntax for to lower case in this context… im gonna look now

6

What’s in those arrays after you split? I’m suspicious

7

strings… hahaha containing the full word
it never split like i intended… why?

8

but the rest of the code still seems to work with it

9

I don’t think it worksas you intend if it not an array of letters

10

check still is “h” then “e” then “y”

11

unless its because .includes() works differently

12

Oh, you aren’t using those arrays. I’d delete them.

1 Like
13

why isnt any of them returning true ??

:no_mouth: :melting_face:

14

What’s count for one of those tests?

15

for hey the count is 2 …

16

console.log(mutation([“ate”, “date”]))
//count 0 1 2 3 false

17

What about a case that is supposed to be true?

18

i actually resolved it… thanks forthe guidance and the making me not feel alone. helps a lot

1 Like
19

can i show it here to you?
do you not really need to see it?
haha
would you wanna see what it ended up being?

20

Go for it. I’m curious