Basic JavaScript - Counting Cards switch with if-else doesn't works

JavaScript
1

Tell us what’s happening:
I don’t understand how to go with this problem…I have tried switch with if-else block inside cases but that isn’t working out.

Your code so far

let count = 0;

function cc(card) {
  // Only change code below this line
  switch(card){
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
      count+=1;
      if(count>0){
        return count+'Bet';
        }
      else{
        return count+'Hold';}
      break;
    case 7:
    case 8:
    case 9:
      count+=0;
      if(count>0){
        return count+'Bet';}
      else{
        return count+'Hold';}
      break;
    case 10:
    case 'J':
    case 'Q':
    case 'K':
    case 'A':
      count-=1;
      if(count>0){
        return count+'Bet';}
      else{
        return count+'Hold';}
      break;
  }
  

  return "Change Me";
  // Only change code above this line
}

cc(2); cc(3); cc(7); cc('K'); cc('A');

Challenge: Basic JavaScript - Counting Cards

Link to the challenge:

2

Your code works but for the fact that it returns ‘1Bet’ or ‘-2Hold’ because you haven’t accounted for spacing in your returned string.

You could also tidy up your function a bit by only having one return statement at the end of your function, outside your switch statement, instead of having a redundant return "Change Me" statement.

3

Thanks , I didn’t see the spacing part.
Also would you suggest that using one if-else block after switch , I thought break in switch would lead to exit from the function …I guess it would only lead to exit from switch.

4

Yes, the break only breaks out of the switch statement. It doesn’t act as a function return. So you can put whatever code you like after the switch statement, before you return out of the function.

5

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