Basic JavaScript - Escaping Literal Quotes in Strings

JavaScript
1

I am writing as per the criteria but i didn’t get it where i am going wrong.

const myStr = "I am a \"double quoted\" string inside \"double quotes\"."; // Change this line; 
// Change this line
console.log("myStr1 = ",myStr);

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Challenge: Basic JavaScript - Escaping Literal Quotes in Strings

Link to the challenge:

2

The console.log statement is there to help you debug.

What do you get from it right now?

3

Yeah, it’s confusing. Read the instructions closely:

You should use two double quotes (" ) and four escaped double quotes (\" ).

It is counting the double quotes in your code. You have some extras in you console.log, it’s throwing off the test.

4

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