Basic JavaScript - Profile Lookup

I cannot understand why the return “No such contact” is outside the for loop? I mean it should be the else part of first if statement where some name is not matched to firstName. But why that return is outside the loop

 // Setup
const contacts = [
    firstName: "Akira",
    lastName: "Laine",
    number: "0543236543",
    likes: ["Pizza", "Coding", "Brownie Points"],
    firstName: "Harry",
    lastName: "Potter",
    number: "0994372684",
    likes: ["Hogwarts", "Magic", "Hagrid"],
    firstName: "Sherlock",
    lastName: "Holmes",
    number: "0487345643",
    likes: ["Intriguing Cases", "Violin"],
    firstName: "Kristian",
    lastName: "Vos",
    number: "unknown",
    likes: ["JavaScript", "Gaming", "Foxes"],

function lookUpProfile(name, prop) {
  // Only change code below this line

  for(let i = 0; i < contacts.length; i++){
        if(name === contacts[i].firstName){
                return contacts[i][prop];
              return "No such property";
                 return "No such contact";


  // Only change code above this line

lookUpProfile("Akira", "likes");

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Challenge: Basic JavaScript - Profile Lookup

Link to the challenge:

Thats essentially what its doing. The inner part of the if statement only runs if it finds a contact, and then it looks for the property. If there is a property then inner if returns the contact with the property, or if there is no property then it returns the no property message. However, if it doesn’t find a contact then it runs the contact message

Whenever i feel confused about my logic, i draw out flowchart / use pseudo-code to make my mind clearer.

An add-on:

if you place return inside the for-loop:

You are not scanning for whole array. Your function immediately stops when the first arrayitem do not matched. Doing so, it is like “break” in a for-loop, which you dont want.

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