Basic JavaScript - Stand in Line

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.
Pls can someone help me out.
Your code so far

function nextInLine(arr, item) {
  // Only change code below this line
  testArr.pop(5)
  item = testArr.shift(5)
  
  return item;
  // Only change code above this line
}

// Setup
let testArr = [1, 2, 3, 4, 5];

// Display code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr, 6));
console.log("After: " + JSON.stringify(testArr));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/109.0.0.0 Safari/537.36

Challenge: Basic JavaScript - Stand in Line

Link to the challenge:

2

Here are the challenges I couldn’t solve

  • nextInLine([2], 1) should return 2

  • Waiting:nextInLine([5,6,7,8,9], 1) should return 5

  • Waiting:After nextInLine(testArr, 10), testArr[4] should be 10

4

Pls I don’t understand the challenges.

6

Not your link :sweat_smile:, the challenges of my question. I already passed that one.

7

These are the remaining challenges.

9

I’ve removed it from the code.

11

This is the new code

 testArr.pop()
  item = testArr.shift()
  testArr[4] = 10
  return item;
13

Thank you It isn’t suppose to be in the code. But it removes the last element of an array.

15

Sorry, I’m a bit confused now.

17 
testArr.push(5)
  item = testArr.shift()
  testArr.push(6)
  item = testArr.shift()
  testArr.push(7)
  item = testArr.shift()
  testArr.push(8)
  item = testArr.shift()
  testArr.push(9)
  item = testArr.shift()
  testArr[4] = 10
  return item;
19

Thank you very much :grin:.

20

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