Basic JavaScript - Use Recursion to Create a Countdown

JavaScript
1

Tell us what’s happening:
The reason why this works seems very technical but I thought I got the gist of it. But I understood that the push(n) function only added n to the end of the array. Why then if I delete the .push part does it return a completely empty array instead of an array that counts up to 4?

Your code so far

function countup(n) {
  if (n < 1) {
    return [];
  } else {
    const countArray = countup(n - 1);
    countArray.push(n);
    return countArray;
  }
}
console.log(countup(5));

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Challenge: Basic JavaScript - Use Recursion to Create a Countdown

Link to the challenge:

2

because if you remove push you remove it for all calls to countup, meaning that the call to countup(n - 1) always results in an empty array

3

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