Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

If I run this code, I cannot fulfil this step. “Failed: 7. With 1900 as the value of the year variable, the result should be 1900 is not a leap year…”

and I try changing the value of the “let year” variable to this: “let year = 1900;” After that I ran the code again, and now I haven’t not fullfil these two steps “Failed:5. With 2024 as the value of the year variable, the result should be 2024 is a leap year…” "Failed: 6. With 2000 as the value of the year variable, the result should be."2000

Your code so far


function isLeapYear(yearNum){
  if(year%4==0){
    if(year%400==0){
     return `${yearNum} is a leap year.`;
    }else if(year%100==0){
      return `${yearNum} is not a leap year.`;
    }else{
      return `${yearNum} is a leap year.`;
    }
  }else{
    return `${yearNum} is not a leap year.`;
  }
}
let year = 2000;
const result = isLeapYear(year);
console.log(result);

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Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

1 Like
2

Hello,
look at the function isLeapYear, you are using a parameter called yearNum yet you are using another parameter in your code called year which you did not define at the top of the function, so the function is using the variable year defined outside of it which causes some test to fail.To fix this, change the year variable inside the function body to be yearNum