Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

I don’t understand why I am not passing the tests. I am failing tests 6 and 7 when I put the variable year with value 2024 and then the result variable. But if I change year for 2000 then test number 5 and 7 fails. I put the logs of “if1” to check if it is getting the return from the correct if

Your code so far


function isLeapYear (numYear) {
  if (numYear % 4 == 0 && numYear % 100 == 0 && numYear % 400 == 0){
    console.log("if1")
    return `${year} is a leap year.`
  } else if (numYear % 4 == 0 && numYear % 100 == 0){
    console.log("if2")
    return `${year} is not a leap year.`
  } else if (numYear % 4 == 0){
    console.log("if3")
    return `${year} is a leap year.`
  } else {
    console.log("if4")
    return `${year} is not a leap year.`
  }
}

let year = 2000
let result = isLeapYear(year)
console.log(result)

year = 2024
result = isLeapYear(year)
console.log(result)

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Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

2

double check your returns

3

Welcome to the forum @Adum05 !

Are you using your numYear parameter throughout the body of your function?

4

Thank you both I found the problem and it was such as you suggested. Thanks