Build a Lunch Picker Program - Build a Lunch Picker Program

JavaScript
1

Tell us what’s happening:

I’m unable to pass test #26, which says that the function showLunchMenu should have a single parameter. My function only has a single parameter but it doesn’t pass the test. Any idea why? Thanks in advance. - Dtrizzle

Your code so far

function addLunchToEnd(arr, item) {
  arr.push(item);
  console.log(`${item} added to the end of the lunch menu.`);
  return arr;
}

function addLunchToStart(arr, item) {
    arr.unshift(item);
    console.log(`${item} added to the start of the lunch menu.`);
    return arr;
  }

function removeLastLunch(arr) {
    if (arr.length > 0) {
        let lastItem = arr.pop();
        console.log(`${lastItem} removed from the end of the lunch menu.`);
    } else {
        console.log("No lunches to remove.");
    }
    return arr;
}

function removeFirstLunch(arr) {
    if (arr.length > 0) {
        let firstItem = arr.shift();
        console.log(`${firstItem} removed from the start of the lunch menu.`);
    } else {
        console.log("No lunches to remove.");
    }
    return arr;
}

function getRandomLunch(arr) {
    if (arr.length > 0) {
        let randomIndex = Math.floor(Math.random() * arr.length);
        console.log(`Randomly selected lunch: ${arr[randomIndex]}`);
    } else {
        console.log("No lunches available.");
    }
}

function showLunchMenu(arr = []) {
    if (arr.length > 0) {
        console.log(`Menu items: ${arr.join(', ')}`);
    } else {
        console.log("The menu is empty.");
    }
}

const lunches = [];
addLunchToEnd(lunches, "Tacos");
addLunchToEnd(["Pizza", "Tacos"], "Burger");
addLunchToStart(lunches, "Sushi");
addLunchToStart(["Burger", "Sushi"], "Pizza");
removeLastLunch(["Sushi", "Pizza"], "Noodles");
removeFirstLunch(["Salad", "Eggs", "Cheese"]);
showLunchMenu();
showLunchMenu(["Greens", "Corns", "Beans"]);

Your browser information:

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Challenge Information:

Build a Lunch Picker Program - Build a Lunch Picker Program

2

Welcome to the forum @dtrizzle

Try it without the assignment.

Happy coding

3

That worked! Thank you. Given that it meets the requirements (“single parameter”) as listed, should I report a bug? Just thinking about people in the future who might have the same issue.

4

Hi there. You already have array []to store data, doesn’t need to assign a new one to the parameter.

5

It seems the tests uses the length property on the function, but default parameters do not count toward that length, so your function was failing the test as the Function.length was 0 instead of the expected 1