Build a Music Player - Step 36

JavaScript
1

Tell us what’s happening:

I have no idea if I am formatting anything right in this step. I am not passing the 2nd test, and need help understanding. thanks :slight_smile:

Your code so far

<!-- file: index.html -->


/* file: styles.css */


/* file: script.js */
// User Editable Region

const highlightCurrentSong = () => {
  
 const songs = document.querySelectorAll(".playlist-song");
  const ariaCurrent = songs.querySelector('aria-current="true"')
  if(ariaCurrent){
    ariaCurrent.removeAttribute("aria-current")
  }
  
}

// User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/138.0.0.0 Safari/537.36 Edg/138.0.0.0

Challenge Information:

Build a Music Player - Step 36

2

songs is not an element, because querySelectorAll returns an array-like structure

also you don’t need to select again the .playlist-song elements, as it is already done on line 1

also there is an other issue, querySelector checks the elements inside the element you are using it on, so you need to use a different logic to check if a .playlist-song element also has aria-current set to true

3

Ok. so I use playlistSongs instead of calling songs is what you are saying? If that is the case I am still confused on what syntax I should use.

 if(playlistSongs === 'aria-current="true"'){
    playListSongs.removeAttribute("aria-current")
  }

this is what I updated to but I am still not passing test 2

4

What is the requirement of test 2?

Double check the related User Story and ensure it’s followed precisely.

What line of code is involved?

5
  1. Your highlight currentSong function should use the removeAttribute method to remove the aria-current attribute from the .playlist-song element with aria-current=“true” if that element exists.
6

I got it thank you, I just had to use forEach! :+1:

2 Likes
7

let me ask you for so when i try to use forEach it return me typeerror

8

oh what an easy it was, although i tried more and more to use forEach and filter methods but i faild, but you encourage me and now i succeed i donno how haha :slight_smile:

9

please create your own topic for your questions

1 Like