Build a Number Pattern Generator - Build a Number Pattern Generator

Python
1

Tell us what’s happening:

Objectives 3, 4, and 5 are rejected, and I think I know why but I’m not sure how to elegantly solve it. It doesn’t want an extra space at the end of the list of numbers.

Entering 0.4 gives
Argument must be an integer value.
Argument must be an integer greater than 0.

Entering -2 gives
Argument must be an integer greater than 0.

Entering False gives
Argument must be an integer greater than 0.

Entering True gives
1

Entering any string (in this case, “blah”) gives
Traceback (most recent call last):
File “main.py”, line 12, in
NameError: name ‘blah’ is not defined

Entering any positive integer works just fine.

Your code so far

def number_pattern(n):
    if not isinstance(n, int):
        return "Argument must be an integer value."
    if n < 1:
        return "Argument must be an integer greater than 0."
    else:
        num = ""
        for i in range(1, n+1):
            num += str(i) + " "
        return num

print(number_pattern(4))

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Challenge Information:

Build a Number Pattern Generator - Build a Number Pattern Generator

2

Hi @LingGeekRain

To help debug, try add an 'x’ to the end of the returned value.

Happy coding

3

I don’t understand what you mean. Add an x where exactly?

4

Contenacate the string 'x'on the last line of the function, after the num variable.

1 Like
5

Got ya. Okay, turning return num into return num + "x" and calling the function with 12 gives

1 2 3 4 5 6 7 8 9 10 11 12 x

Which means I no longer have any idea why objectives 3, 4, and 5 are rejected.

6

there is a space between 12 and the x, there isn’t a space at the end of the requested output

1 Like
7

When you use the for loop, You end up adding an extra space at last.

1 Like
8

Okay, so that is the problem I thought it was. Now to come up with a clever if statement (she said, not feeling particularly clever).

9

I figured it out, no if statement required, just a slight re-work of the for loop :grin: