Build a Number Pattern Generator - Build a Number Pattern Generator

Python
1

Tell us what’s happening:

I already passed the exercise, I’m just curious as to how I can make the pattern making portion “look better”. Starting with a string that already has “1” in it, making the range be (n-1), and using (num + 2) feels a bit too “brute force-y” for my liking.

Your code so far

def number_pattern(n):
    if type(n) != int:
        return "Argument must be an integer value."
    if n < 1:
        return "Argument must be an integer greater than 0."

    pattern = "1"

    for num in range(n-1):
        pattern += " " + str(num +2)

    return pattern

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Challenge Information:

Build a Number Pattern Generator - Build a Number Pattern Generator

2

We have blurred this solution (with [spoiler][/spoiler] tags) so that users who have not completed this challenge can read the discussion in this thread without giving away the solution.

3

why don’t you use range to start from the value you want to start with? so 2, and end with n?

you may want to review about range

1 Like
4

Admittedly, it’s because I rewrote the code while looking at the terminal, so I adjusted on the fly haha. But I see what you mean, I forgot about adding arguments to the range to streamline it.

But am I correct in thinking that I still need to use n+1 for the range since it’s not inclusive, and so that I can avoid having to use n+1 in the for concatenation portion? So now it looks like this:


    pattern = "1"

    for num in range(2,n+1):

        pattern += " " + str(num)

Also, starting with “1“ is the only way I thought of being able to avoid having an unnecessary whitespace either at the beginning or at the end of the string, apart from having to manually remove it later on. Is there a different way that I missed?

5

you could add a conditional so to add the space only when needed, and not add it when not needed

1 Like
6

All the tests pass in the console output, but it shows I’m failing:
3. number_pattern(4) should return 1 2 3 4.

Turns out I missed the critical text return in the Objective “number_pattern(n) should “return”… I used print()because why not. :blush:

7

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