Tell us what’s happening:
my code worked as expeected but the answers are printed vertically. How can i make it horizontal?

Your code so far
```
def arithmetic_arranger(problems, show_answers=False):
if len(problems)>5:
print('Error: Too many problems.')
for items in problems:
lists = items.split()
integers = int(lists[0])
operator = lists[1]
operation = int(lists[2])
#print(operator)
if operator == '+':
answer = integers + operation
elif operator == '-':
answer = integers - operation
else:
print("Error: Operator must be '+' or '-'.")
if isinstance(integers and operation, int) ==True:
pass
else:
print('Error: Numbers must only contain digits.')
if integers>=10000 or operation>=10000:
print('Error: Numbers cannot be more than four digits.')
if integers > operation:
L1 = lists[0].rjust(len(lists[0])+2)
L2 = lists[2].rjust(len(lists[0])+1)
L3 = '-' * (len(lists[0])+2)
L4 = str(answer).rjust(len(lists[0])+2)
else:
L1 = lists[0].rjust(len(lists[2])+2)
L2 = lists[2].rjust(len(lists[2])+1)
L3 = '-' * (len(lists[2])+2)
L4 = str(answer).rjust(len(lists[2])+2)
print(L1)
print(lists[1]+L2)
print(L3)
if show_answers == True:
print(L4)
arithmetic_arranger(["32 - 698", "1 - 3801", "45 + 43", "123 + 49", "988 + 40"], True)
```

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Challenge Information:
Build an Arithmetic Formatter Project - Build an Arithmetic Formatter Project

There isn’t really any special trick, to make them print horizontally. How would you print few numbers in a single line?

please double check the instructions, you need to return the output not print it

but the function go through the list one by one
I can’t print all the integers first before doing the calculation

sanity
June 14, 2024, 7:23am
5
Why not? Or rather what would need to be changed in code to be able to do that?

Think of the way an old dot matrix printer prints, line by line.

Think of what’s on each line:

```
prob1num1 prob2num2
prob1operator prob1num2 prob2operator prob2num2
```

Break up the variables, organize and print them out the way you need to. You’ll need to print `prob1num1`

first, some spaces, and then `prob2num2`

then a `\n`

, right?

but i need to return a string as the answer
how can i join strings to a multiple line string?

```
def arithmetic_arranger(problems, show_answers=False):
F1 = ''
F2 = ''
F3 = ''
F4 = ''
Final = ''
if len(problems)>5:
print( 'Error: Too many problems.')
for items in problems:
lists = items.split()
integers = int(lists[0])
operator = lists[1]
operation = int(lists[2])
#print(operator)
if operator == '+':
answer = integers + operation
elif operator == '-':
answer = integers - operation
else:
return "Error: Operator must be '+' or '-'."
if isinstance(integers and operation, int) ==True:
pass
else:
return 'Error: Numbers must only contain digits.'
if integers>=10000 or operation>=10000:
return 'Error: Numbers cannot be more than four digits.'
if integers > operation:
L1 = lists[0].rjust(len(lists[0])+2)
L2 = lists[2].rjust(len(lists[0])+1)
L3 = '-' * (len(lists[0])+2)
L4 = str(answer).rjust(len(lists[0])+2)
else:
L1 = lists[0].rjust(len(lists[2])+2)
L2 = lists[2].rjust(len(lists[2])+1)
L3 = '-' * (len(lists[2])+2)
L4 = str(answer).rjust(len(lists[2])+2)
# L2 += operator
F1 += L1 + ' '
F2 += operator+ L2 + ' '
F3 += L3 + ' '
F4 += L4 + ' '
if show_answers==True:
Final = F1 + '\n' + F2 + '\n' + F3 + '\n' + F4
else:
Final = F1 + '\n' + F2 + '\n' + F3
# print(Final)
return Final
arithmetic_arranger(["3801 - 2", "123 + 49"])
```

printing the answer is perfectly matched as requested
but it is still incorrect when using the return statement

ilenia
June 17, 2024, 7:14am
11
You can get the string rapresentation if you wrap your output in `repr`

before printing: `print(repr(arithmetic_arranger(["3801 - 2", "123 + 49"])))`

. In this way it is easier to confront with the expected output

```
Actual: ' 3801 123 \n- 2 + 49 \n------ ----- '
expected: ' 3801 123\n- 2 + 49\n------ -----'
```

you have extra spaces before the new line character

Finally got it !!!
Thanks for the help from every one of you

1 Like