I have a problem when uploading image
here is some code on react native expo
import React, { Component } from 'react';
import {
ActivityIndicator,
Button,
Clipboard,
Image,
Share,
StatusBar,
StyleSheet,
Text,
TouchableOpacity,
View,
} from 'react-native';
import { Constants } from 'expo';
import * as ImagePicker from 'expo-image-picker';
import * as Permissions from 'expo-permissions';
export default class App extends Component {
state = {
image: null,
uploading: false,
};
render() {
let {
image
} = this.state;
return (
<View style={styles.container}>
<StatusBar barStyle="default" />
<Text
style={styles.exampleText}>
Example: Upload ImagePicker result
</Text>
<Button
onPress={this._pickImage}
title="Pick an image from gallery"
/>
<Button onPress={this._takePhoto} title="Take a photo" />
{this._maybeRenderImage()}
{this._maybeRenderUploadingOverlay()}
</View>
);
}
_maybeRenderUploadingOverlay = () => {
if (this.state.uploading) {
return (
<View
style={[StyleSheet.absoluteFill, styles.maybeRenderUploading]}>
<ActivityIndicator color="#fff" size="large" />
</View>
);
}
};
_maybeRenderImage = () => {
let {
image
} = this.state;
if (!image) {
return;
}
return (
<View
style={styles.maybeRenderContainer}>
<View
style={styles.maybeRenderImageContainer}>
<Image source={{ uri: image }} style={styles.maybeRenderImage} />
</View>
<Text
onPress={this._copyToClipboard}
onLongPress={this._share}
style={styles.maybeRenderImageText}>
{image}
</Text>
</View>
);
};
_share = () => {
Share.share({
message: this.state.image,
title: 'Check out this photo',
url: this.state.image,
});
};
_copyToClipboard = () => {
Clipboard.setString(this.state.image);
alert('Copied image URL to clipboard');
};
_takePhoto = async () => {
const {
status: cameraPerm
} = await Permissions.askAsync(Permissions.CAMERA);
const {
status: cameraRollPerm
} = await Permissions.askAsync(Permissions.CAMERA_ROLL);
// only if user allows permission to camera AND camera roll
if (cameraPerm === 'granted' && cameraRollPerm === 'granted') {
let pickerResult = await ImagePicker.launchCameraAsync({
allowsEditing: true,
aspect: [4, 3],
});
this._handleImagePicked(pickerResult);
}
};
_pickImage = async () => {
const {
status: cameraRollPerm
} = await Permissions.askAsync(Permissions.CAMERA_ROLL);
// only if user allows permission to camera roll
if (cameraRollPerm === 'granted') {
let pickerResult = await ImagePicker.launchImageLibraryAsync({
allowsEditing: true,
aspect: [4, 3],
});
this._handleImagePicked(pickerResult);
}
};
_handleImagePicked = async pickerResult => {
let uploadResponse, uploadResult;
try {
this.setState({
uploading: true
});
if (!pickerResult.cancelled) {
uploadResponse = await uploadImageAsync(pickerResult.uri);
uploadResult = await uploadResponse.json();
this.setState({
image: uploadResult.location
});
}
} catch (e) {
console.log({ uploadResponse });
console.log({ uploadResult });
console.log({ e });
alert('Upload failed, sorry :(');
} finally {
this.setState({
uploading: false
});
}
};
}
async function uploadImageAsync(uri) {
let apiUrl = 'http://192.168.0.17/upload-api/uploading.php';
let uriParts = uri.split('.');
let fileType = uriParts[uriParts.length - 1];
let formData = new FormData();
formData.append('fileToUpload', {
uri,
name: `fileToUpload.${fileType}`,
type: `image/${fileType}`,
});
let options = {
method: 'POST',
body: formData,
headers: {
Accept: 'application/json',
'Content-Type': 'multipart/form-data',
},
};
return fetch(apiUrl, options);
}
and here is my PHP Code
<?php
//Define your host here.
$hostname = "localhost";
//Define your database User Name here.
$username = "root";
//Define your database Password here.
$password = "";
//Define your Database Name here.
$dbname = "mydatabase";
$conn = mysql_connect($hostname, $username, $password);
mysql_select_db($dbname, $conn);
// Type your website name or domain name here.
$domain_name = "http://192.168.0.17/upload-api/" ;
// Image uploading folder.
$target_dir = "uploads";
// Generating random image name each time so image name will not be same .
$target_dir = $target_dir . "/" .rand() . "_" . time() . ".jpeg";
// Receiving image tag sent from application.
$img_tag = $_POST["image_tag"];
// Receiving image sent from Application
if(move_uploaded_file($_FILES['image']['tmp_name'], $target_dir)){
// Adding domain name with image random name.
$target_dir = $domain_name . $target_dir ;
// Inserting data into MySQL database.
mysql_query("insert into image_upload_table ( image_tag, image_path) VALUES('$img_tag' , '$target_dir')");
$MESSAGE = "Image Uploaded Successfully." ;
// Printing response message on screen after successfully inserting the image .
echo json_encode($MESSAGE);
}
?>
is there any problem here? cause upload always failed and didnt insert to database
thank you