Card Counting Switch Confusion

JavaScript
1

So, I encountered a really confusing issue while trying to solve this. The solution for the switch approach looks like this:
switch (card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
break;

That’s fine, but, while looking through the hints and other peoples’ solutions, I saw someone formatting their switch like this:

switch (card) {
case 2,3,4,5,6:
count++;
break;

This is where my problem is; When using this person’s format, I found that count would never increase. However, formatting cases 10, J, Q, K, and A the same way would decrease count properly (I tested this in Chrome’s console). Could anyone explain this one to me? Is there an issue with laying out cases horizontally?

2

A case only matches against one value or condition. This should not work.

1 Like
3

That would explain why case 2,3,4,5,6: would never actually add to the count. But, doing the same thing for case 10, ‘J’, ‘Q’, ‘K’, ‘A’: actually worked (count-- would work). That’s what had me stumped for quite a while.

4

That should also not work.

5

Then I’m even more confused than before. xD Well, I’m past it already, but I wanted to try and get some understanding on how that actually worked (or didn’t work in this case). Appreciate the quick response.

6

In each case, the condition is strictly compared, so

switch (card) {
  case 1, 2, 3:
  ...
}

is the same as

if (card === 1, 2, 3) {
  ...
}

and that is not a valid comparison.

7

with all the cards? it will with only one of them