Compare Scopess of the var and let Keywords

JavaScript
#1

Tell us what’s happening:

printNumTwo() returned the correct value because three different i variables with unique values (0, 1, and 2) were created by the let keyword within the loop statement.

I don’t understand the above explanation, can someone please explain?

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/compare-scopes-of-the-var-and-let-keywords

#2 
'use strict';
let printNumTwo;
for (let i = 0; i < 3; i++) {
  if (i === 2) {
    printNumTwo = function() {
      return i;
    };
  }
}
console.log(printNumTwo());
// returns 2
console.log(i);
// returns "i is not defined"

printNumTwo is declared outside the for loop, console.log(i) returns not define because i declared in only the for loop, we can’t access outside that loop.

#3

I don’t understand why the explanation says that 3 different ‘i’ with unique values (0,1 and 2) were created.

#4

Loop runs once, i is 0
Loop runs again, i is 1
Loop runs again, i is 2

#5

@DanCouper But i gets updated right? it doesn’t store 0 and 1?

#6