Counting Cards Question?

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.
I am curious why the code did not pass the test cases. If you console.log the two cases that fail it returns the expected output.

  **Your code so far**


let count = 0;

function cc(card) {
// Only change code below this line
switch(card) {
  case 2:
  case 3:
  case 4:
  case 5:
  case 6:
    count++
    return count + ' Bet'
    break;
  case 7:
  case 8:
  case 9:
    return count + ' Hold'
    break;
  case 10:
  case 'J':
  case 'Q':
  case 'K':
  case 'A':
    count--
    return count + ' Hold'
    break;
}
return "Change Me";
// Only change code above this line
}
// if you console.log the two test cases that fail they give the correct output? 
console.log(cc(2, 'J', 9, 2, 7))
//console.log(cc(2, 2, 10))
cc(2); cc(3); cc(7); cc('K'); cc('A');

  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/97.0.4692.71 Safari/537.36

Challenge: Counting Cards

Link to the challenge:

2

You didn’t ask your question or tell us what you need help with.

3

I apologize, I wrote it in the comments but should have clairified. I am curious why the code did not pass the test cases. If you console.log the two cases that fail it returns the expected output.

4

The returned string should have nothing to do with the value of the card.

5

As Jeremy pointed out, you will decide what to return using different logic conditions than you use to update the count variable. I suggest looking at

return "Change Me";

and changing the code there.

6

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