Counting Cards, yep its me again

JavaScript
1

Tell us what’s happening:

Please dont kick me off for asking too many questions!! I havent coded in a long time and im reallllllllyyyy trying to research, fix, and ask for help before just going straight to the solution. thank you!!

Your code so far


var count = 0;

function cc(card) {
  // Only change code below this line
  switch(card){
    case 2: count++;
    case 3:count++;
    case 4:count++;
    case 5: count++;
    case 6: count++;
  break;
    case 10: count--;
    case 'J':count--;
    case 'Q':count--;
    case 'K':count--;
    case 'A':count--;
  }
  if (count>0){
   return count," ",'Bet';
  }else if(count<=0){
    return count," ",'Hold';
  }
  // Only change code above this line
}

// Add/remove calls to test your function.
// Note: Only the last will display
cc(2); cc(3); cc(7); cc('K'); cc('A');

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_6) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/counting-cards/

2

almost there for the switch

The switch statement keeps executing till it reaches a break, so if you get 2 then card++ will actually execute five times

Knowing this you can also reduce the repeated code inside the switch
And you need a break after the last case

This is not correct, you may want to review how to concatenate strings with the + operator

3

‘shiver me timbers’(is what free code camp exclaimed!), i solved it thanks to your help!! Thanks leahleen!