Debug an ISBN Validator - Debug an ISBN Validator

Tell us what’s happening:

can anyone help me i cant figure it out. i dont know what to do

Your code so far

def validate_isbn(isbn, length):
    isbn_str = str(isbn)
    if len(isbn_str) != length:
        print(f'ISBN-{length} code should be {length} digits long.')
        return
    main_digits = isbn_str[0:length]
    given_check_digit = isbn_str[length-1]
    main_digits_list = [int(digit) for digit in main_digits]
    # Calculate the check digit from other digits
    if length == 10:
        total = 0
        for i in range(9):
            total += int(isbn_str[i]) * (10 - i)

        check_char = isbn_str[9]
        if check_char == 'X':
            check_value = 10
        else:
            check_value = int(check_char)

            total += check_value

        if total % 11 == 0:
            print('Valid ISBN Code.')
            return True
        else:
            print('Invalid ISBN Code.')
            return False

    elif length == 13:
        total = 0

    for i in range(13):
        weight = 1 if i % 2 == 0 else 3
        total += int(isbn_str[i]) * weight

    if total % 10 == 0:
        print('Valid ISBN Code.')
        return True
    else:
        print('Invalid ISBN Code.')
        return False
def calculate_check_digit_10(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 9 digits by its corresponding weight (10 to 2) and sum up the results
    for index, digit in enumerate(main_digits_list):
        digits_sum += digit * (10 - index)
    # Find the remainder of dividing the sum by 11, then subtract it from 11
    result = 11 - digits_sum % 11
    # The calculation result can range from 1 to 11.
    # If the result is 11, use 0.
    # If the result is 10, use upper case X.
    # Use the value as it is for other numbers.
    if result == 11:
        expected_check_digit = '0'
    elif result == 10:
        expected_check_digit = 'X'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def calculate_check_digit_13(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 12 digits by 1 and 3 alternately (starting with 1), and sum up the results
    for index, digit in enumerate(main_digits_list):
        if index % 2 == 0:
            digits_sum += digit * 1
        else:
            digits_sum += digit * 3
    # Find the remainder of dividing the sum by 10, then subtract it from 10
    result = 10 - digits_sum % 10
    # The calculation result can range from 1 to 10.
    # If the result is 10, use 0.
    # Use the value as it is for other numbers.
    if result == 10:
        expected_check_digit = '0'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def main():
    user_input = input('Enter ISBN and length: ')
    if "," not in user_input:
        print("Enter comma-separated values.")
    values = user_input.split(',')
    try:  
        isbn = values[0]   # keep as string
        length = int(values[1])
    except ValueError:
        print("Invalid character was found.")
        print("Length must be a number.")
    if length == 10 or length == 13:
        validate_isbn(isbn, length)
    else:
        print('Length should be 10 or 13.')

    

#main()
validate_isbn(080442957X,10)

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/146.0.0.0 Safari/537.36

Challenge Information:

Debug an ISBN Validator - Debug an ISBN Validator

Hi there,

Where in main() are you validating ISBN to make sure it is what’s expected?

Happy coding!

This topic was automatically closed 28 days after the last reply. New replies are no longer allowed.