Debug an ISBN Validator - Debug an ISBN Validator

Tell us what’s happening:

can anyone help me i cant figure it out. i dont know what to do

Your code so far

def validate_isbn(isbn, length):
    isbn_str = str(isbn)
    if len(isbn_str) != length:
        print(f'ISBN-{length} code should be {length} digits long.')
        return
    main_digits = isbn_str[0:length]
    given_check_digit = isbn_str[length-1]
    main_digits_list = [int(digit) for digit in main_digits]
    # Calculate the check digit from other digits
    if length == 10:
        total = 0
        for i in range(9):
            total += int(isbn_str[i]) * (10 - i)

        check_char = isbn_str[9]
        if check_char == 'X':
            check_value = 10
        else:
            check_value = int(check_char)

            total += check_value

        if total % 11 == 0:
            print('Valid ISBN Code.')
            return True
        else:
            print('Invalid ISBN Code.')
            return False

    elif length == 13:
        total = 0

    for i in range(13):
        weight = 1 if i % 2 == 0 else 3
        total += int(isbn_str[i]) * weight

    if total % 10 == 0:
        print('Valid ISBN Code.')
        return True
    else:
        print('Invalid ISBN Code.')
        return False
def calculate_check_digit_10(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 9 digits by its corresponding weight (10 to 2) and sum up the results
    for index, digit in enumerate(main_digits_list):
        digits_sum += digit * (10 - index)
    # Find the remainder of dividing the sum by 11, then subtract it from 11
    result = 11 - digits_sum % 11
    # The calculation result can range from 1 to 11.
    # If the result is 11, use 0.
    # If the result is 10, use upper case X.
    # Use the value as it is for other numbers.
    if result == 11:
        expected_check_digit = '0'
    elif result == 10:
        expected_check_digit = 'X'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def calculate_check_digit_13(main_digits_list):
    # Note: You don't have to fully understand the logic in this function.
    digits_sum = 0
    # Multiply each of the first 12 digits by 1 and 3 alternately (starting with 1), and sum up the results
    for index, digit in enumerate(main_digits_list):
        if index % 2 == 0:
            digits_sum += digit * 1
        else:
            digits_sum += digit * 3
    # Find the remainder of dividing the sum by 10, then subtract it from 10
    result = 10 - digits_sum % 10
    # The calculation result can range from 1 to 10.
    # If the result is 10, use 0.
    # Use the value as it is for other numbers.
    if result == 10:
        expected_check_digit = '0'
    else:
        expected_check_digit = str(result)
    return expected_check_digit
def main():
    user_input = input('Enter ISBN and length: ')
    if "," not in user_input:
        print("Enter comma-separated values.")
    values = user_input.split(',')
    try:  
        isbn = values[0]   # keep as string
        length = int(values[1])
    except ValueError:
        print("Invalid character was found.")
        print("Length must be a number.")
    if length == 10 or length == 13:
        validate_isbn(isbn, length)
    else:
        print('Length should be 10 or 13.')

    

#main()
validate_isbn(080442957X,10)

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Challenge Information:

Debug an ISBN Validator - Debug an ISBN Validator

Hi there,

Where in main() are you validating ISBN to make sure it is what’s expected?

Happy coding!