Diff Two Arrays challenge feedback

Diff Two Arrays challenge feedback
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#1

Hi people,

Just thought I’d post my code for the Diff Two Arrays challenge, it takes advantage of Sets so the nice has() method can be used. However how can I improve this? I feel like 2 for loops doing roughly the same thing is slightly inefficient.

/* jshint esversion: 6 */
function diffArray(arr1, arr2) {
  const filteredSet = new Set();
  const set1 = new Set(arr1);
  const set2 = new Set(arr2);
 
  for(let item of set1) {
    if(set2.has(item)) {
      continue;
    } else {
     filteredSet.add(item);
    }
  }
  
  for(let item of set2) {
   if(set1.has(item)) {
    continue; 
   } else {
    filteredSet.add(item); 
   }
  }
  
  const newArray = Array.from(filteredSet);
  return newArray;
}

diffArray([1, 2, 3, 5, 7, "test string"], [1, 2, 3, 4, 5]);

Some guidance on how to improve this would be great!

Thanks!
James.