Diff two arrays

JavaScript
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Diff Two Arrays

Compare two arrays and return a new array with any items only found in one of the two given arrays, but not both. In other words, return the symmetric difference of the two arrays.

Note: You can return the array with its elements in any order.

Tests

  • Passed:diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]) should return an array.

  • Passed:["diorite", "andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"]should return ["pink wool"].

  • Passed:["diorite", "andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"]should return an array with one item.

  • Failed:["andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] should return ["diorite", "pink wool"].

  • Failed:["andesite", "grass", "dirt", "pink wool", "dead shrub"], ["diorite", "andesite", "grass", "dirt", "dead shrub"] should return an array with two items.

  • Passed:["andesite", "grass", "dirt", "dead shrub"], ["andesite", "grass", "dirt", "dead shrub"]should return [].

  • Passed:["andesite", "grass", "dirt", "dead shrub"], ["andesite", "grass", "dirt", "dead shrub"]should return an empty array.

  • Passed:[1, 2, 3, 5], [1, 2, 3, 4, 5]should return [4].

  • Passed:[1, 2, 3, 5], [1, 2, 3, 4, 5]should return an array with one item.

  • Failed:[1, "calf", 3, "piglet"], [1, "calf", 3, 4] should return ["piglet", 4].

  • Failed:[1, "calf", 3, "piglet"], [1, "calf", 3, 4] should return an array with two items.

  • Passed:[], ["snuffleupagus", "cookie monster", "elmo"] should return ["snuffleupagus", "cookie monster", "elmo"].

  • Passed:[], ["snuffleupagus", "cookie monster", "elmo"] should return an array with three items.

  • Failed:[1, "calf", 3, "piglet"], [7, "filly"] should return [1, "calf", 3, "piglet", 7, "filly"].

  • Failed:[1, "calf", 3, "piglet"], [7, "filly"] should return an array with six items

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function diffArray(arr1, arr2) {

const small = arr1.length > arr2.length ? arr2 : arr1
const big = arr1.length > arr2.length ? arr1 : arr2

const newArr = big.filter(x => !small.includes(x));
return newArr;
}

diffArray([1, 2, 3, 5], [1, 2, 3, 4, 5]);

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