Drop it I cant get it why we are using these instead of the normal ones (arr.length,arr[i])

JavaScript
1

Tell us what’s happening:

Does anybody knows why we are using arr[0] instead of arr[i] ?
and why we created a variable if arr.length. ???
Thank you

Your code so far


function dropElements(arr, func) {
// drop them elements.
var times = arr.length;
for (var i = 0; i < times; i++) {
  if (func(arr[0])) {
    break;
  } else {
    arr.shift();
  }
}
return arr;
}

// test here
dropElements([1, 2, 3, 4], function(n) {
return n >= 3;
});

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/88.0.4324.104 Safari/537.36.

Challenge: Drop it

Link to the challenge:

2

Whoever wrote this code is choosing to modify the array as they are looping over it. That’s why arr[i] wouldn’t work.

1 Like
3

Hello, Can you please explain more ? Thank you for your time!!

4

shift() removes the first element from the array, so every time the loop runs the indices of all values in the array shift by one. arr[0] is different every time.

Note: this solution works, but it isn’t one I would recommend.

5

I reordered the solutions in the guide because I also do not like this solution.

1 Like
6

Alriiiiiiight got it !!! Thank you for your help :mechanical_arm:

1 Like
7

I’m glad I could help. Happy coding!

3 Likes
8

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