ES6 - Use the Spread Operator to Evaluate Arrays In-Place

JavaScript
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I don’t understand this explanation one the null requirement. Why do you not need max and apply methods anymore once you use spread?

And why you need them to avoid NaN if you don’t spread?

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Challenge: ES6 - Use the Spread Operator to Evaluate Arrays In-Place

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Math.max() expects numbers
arr is not a number, but an array, so writing Math.max(arr) you are feeding something that is not a number to a method that expects a number, so it returns NaN

Math.max.apply(null, arr) is a way to use a method that accepts multiple arguments with an array.
The spread operator spread the array to multiple arguments when you do Math.max(...arr) so that’s not needed anymore.
It can be confusing if you don’t already know how it was done before.

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