Falsy Bouncer - is this algorithm too simple?

JavaScript
1

Tell us what’s happening:
This topic suggests converting the array values to boolean. I wasn’t sure how to do that, but I knew I could just check each value to see if it was a truthy and filter on that and so that’s what I did. Is this too simple a solution and if so did I miss the point of this exercise? (ps. how do I convert something to a boolean type?)
pps. to be perfectly clear, the code below passes the challenge, but it just seems too suspiciously easy.

Your code so far


function bouncer(arr) {
  // Don't show a false ID to this bouncer.
  return arr.filter(item => item);
}

bouncer([7, "ate", "", false, 9]);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-algorithm-scripting/falsy-bouncer

1 Like
2

Your solution portrays exactly what the lesson is attempting to teach. You can simply return the value via the filter which will coerce the value to a Boolean by default. Hence, only truthy values will be returned.

3

Looks okay since if the item is true, then it won’t be filtered.

It’s easy becasue of filter and arrow function stuffs (some devs call it lambda).

I prefer create a empty array, and in a for loop check each element, and push them if they not respond to false.

1 Like
5

thanks for the quick response. I wasn’t entirely sure that there was something like a type cast or something that I should be learning. (I’m too used to strongly typed languages)

6

in a real dev situation I’m 100% sure that I would handle it the same (with a for loop) because for loops are just so much easier to read than these “lambda” functions. Thanks for sharing your thoughts.