Final test of "Intermediate Algorithm Scripting: Arguments Optional" - SOLVED

JavaScript
1

Tell us what’s happening:
My code won’t pass the last challenge, and I’m confused by it. It looks to me like a multiplication of the output of my function (which in that case would be another function since there’s only one argument) with the array, [3]. But the output of that would have nothing to do with my function, would it? And I know my function is working correctly in outputting another function when there’s only one argument because it’s passing the other tests. I don’t know how I’m supposed to pass this test.

**EDIT: On second thought, I guess the final challenge is passing the array [3] into the function output by calling addTogether(2). But I still don’t see why it’s not working since it passed Tests 4 and 5.

Your code so far


function addTogether() {
for (let i=0; i<arguments.length; i++) {
  if (typeof arguments[i] !== 'number') return undefined;
}
if (arguments.length === 2) {
  console.log("sum ", (arguments[0] + arguments[1]));
  return (arguments[0] + arguments[1]);
}
else if (arguments.length === 1) {
  let arg = arguments[0];
  console.log("arg: ", arg);
  let func = function(x) {
    return x + arg;
  }
  return func;
}
}

addTogether(2,3);

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User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:81.0) Gecko/20100101 Firefox/81.0.

Challenge: Arguments Optional

Link to the challenge:

2

This function needs to do input validation as well.

3

Yep, just figured that out and came here to mark it solved. But thanks.