Finding Number in String

JavaScript
#1

Hello.

I am trying to return true if there is a number within the string and false if there are none, but I think I am getting confused with how my conditional equates (possibly due to some automatic type conversion).

I am only splitting the string into a character array as my attempt to compare numbers with charAt() also failed.

I DO NOT want to use regex.

Thank you :slight_smile:

function findTicketPrices (emailString) {
  let splitString = emailString.split("")
  for (let i = 0; i < splitString.length; i++) {
    for (let j = 0; j < 10; j++) {
      if (j == splitString[i]) {
        return true;
      }
    }
  }
  return false;
}
#2

Loop through the string, if a character parses as a number, return true. Otherwise there aren’t any numbers, return false. You don’t need to split the string or anything, you can just loop through the characters. Eg

for (let char of emailString) {
  const possibleNum = parseInt(char);
  if (!Number.isNaN(possibleNum)) return true;
}
return false;

Edit: sorry, forgot zero is a number, edited example

Or can check the char code, eg

const code = char.charCodeAt();
if (code >= 48 && code <= 57) return true;

Edit again:

Or can check the result of parseInt-ing is a number >= 0, that also works (NaN is the only other response and will return false):

if (parseInt(char) >= 0) return true

Regex is much simpler here, why do you not want to use it?

2 Likes
#3

Wow. Thanks for so much attention!

I am avoiding regex as I am preparing for an exam whereby I will have to explain my understanding of certain JS code. I think regex, due to being more simple, would avoid some of the things I am to cover.

Thank you so much for your carful responses :slight_smile:

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