# Problem 1: Multiples of 3 and 5

## Problem Explanation

- We can find if a number is divisble by another number with the help of
`%`

modulo operator. -
`num1 % num2`

returns`0`

if there’s no remainder while doing`num1/num2`

. - Starting from
`i = 3`

because that’s the first number that’s divisble by 3 or 5, we loop through till the`number`

provided. - If the number is divisible either by 3 or 5, we add that to the variable
`sum`

and finally return it.